NEETPhysics-Electric Charges and Fields
NEET Physics Electric dipole MCQ Question
Type: MCQ-numerical-Hard-Class 12
Two charges of +25 × 10⁻⁹ coulomb and –25 × 10⁻⁹ coulomb are placed 6 m apart. Find the electric field intensity ratio at points 4 m from the centre of the electric dipole (i) on axial line (ii) on equatorial line
A
1000/49
B
49/1000
C
500/49
D
49/500
Correct Answer
Option A
Detailed Explanation
The electric field on the axial line is given by Eₐ = 2kp/r³ and on the equatorial line by Eₑ = kp/r³. The ratio Eₐ/Eₑ = 2. Substituting the values gives 1000/49.
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