NEET Physics Electric dipole MCQ Question
Two charges of +25 × 10⁻⁹ coulomb and –25 × 10⁻⁹ coulomb are placed 6 m apart. Find the electric field intensity ratio at points 4 m from the centre of the electric dipole (i) on axial line (ii) on equatorial line
1000/49
49/1000
500/49
49/500
Correct Answer
Detailed Explanation
The electric field on the axial line is given by Eₐ = 2kp/r³ and on the equatorial line by Eₑ = kp/r³. The ratio Eₐ/Eₑ = 2. Substituting the values gives 1000/49.
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