NEET2019Physics-Elasticity
NEET 2019 Physics Elastic Potential Energy MCQ Question
Type: MCQ-numerical-Medium-Class 11
When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is:
A
1/2 MgL
B
1/2 MgL
C
MgL
D
MgL
Correct Answer
Option A
Detailed Explanation
The elastic potential energy stored in a stretched wire is given by U = 1/2 * k * x², where k is the spring constant and x is the extension. Using Hooke's law and the given conditions, the potential energy is calculated as 1/2 MgL.
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