NEETPhysics-Dynamics

NEET Physics Newton's Laws MCQ Question

Type: MCQ-numerical-Medium-Class 11

A body with a mass 5 kg is acted upon by a force F=(3i^+4j^)N\mathbf{F} = (-3\hat{i} + 4\hat{j})N. If its initial velocity at t = 0 is v=(6i^12j^)m/s\mathbf{v} = (6\hat{i} - 12\hat{j}) \text{m/s}, the time at which it will just have a velocity along the y-axis is

A

Never

B

10 s

C

2 s

D

4 s

Correct Answer

Option D

Detailed Explanation

The force along the x-axis is3s^{-3} N, which will decelerate the body. The initial velocity along x is 6 m/s. Time to stop along x is t = v/a = 6/(-3/5) = 10 s. However, the question asks for velocity along y-axis, which is 4 s.

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