NEET2015Physics-Centre of mass

NEET 2015 Physics Equilibrium MCQ Question

Type: MCQ-numerical-Medium-Class 11

A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is

A

Wxd\frac{Wx}{d}

B

Wdx\frac{Wd}{x}

C

Wdx\frac{W}{d-x}

D

Wd\frac{W}{d}

Correct Answer

Option C

Detailed Explanation

Using the principle of moments, the normal reaction at A is given by RA=WxdR_A = \frac{Wx}{d}.

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