Chemistry-Transition Elements
NEET Chemistry Transition Elements MCQ Question
Type: MCQ-numerical-Medium-Class 12
Calculate the spin-only magnetic moment (in Bohr Magnetons) for a Co²⁺ ion in aqueous solution, assuming it has a d⁷ configuration.
A
87 BM
B
90 BM
C
83 BM
D
5.92 BM
Correct Answer
Option A
Detailed Explanation
Co²⁺ has a d⁷ configuration, which means it has 3 unpaired electrons. The formula for calculating the spin-only magnetic moment is μ = √(n(n+2)), where n is the number of unpaired electrons. Thus, μ = √(3(3+2)) = √15 = 3.87 BM.
Found an issue with this question?