Chemistry-Transition Elements
NEET Chemistry Transition Elements MCQ Question
Type: MCQ-numerical-Medium-Class 12
Calculate the 'spin-only' magnetic moment of a Cr^3+ ion.
A
3.87 BM
B
2.83 BM
C
5.92 BM
D
0 BM
Correct Answer
Option A
Detailed Explanation
Cr^3+ has 3 unpaired electrons (3d^3 configuration). Using the spin-only formula μ = √(n(n+2)), where n = 3, the magnetic moment is √(3(3+2)) = 3.87 BM.
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