Chemistry-Transition Elements

NEET Chemistry Transition Elements MCQ Question

Type: MCQ-numerical-Medium-Class 12

Calculate the 'spin-only' magnetic moment of a Cr^3+ ion.

A

3.87 BM

B

2.83 BM

C

5.92 BM

D

0 BM

Correct Answer

Option A

Detailed Explanation

Cr^3+ has 3 unpaired electrons (3d^3 configuration). Using the spin-only formula μ = √(n(n+2)), where n = 3, the magnetic moment is √(3(3+2)) = 3.87 BM.

Found an issue with this question?