Chemistry-Transition Elements
NEET Chemistry Transition Elements MCQ Question
Type: MCQ-numerical-Easy-Class 12
Calculate the spin-only magnetic moment (in BM) of Co²⁺ ion in its aqueous form.
A
87 BM
B
90 BM
C
73 BM
D
5.92 BM
Correct Answer
Option A
Detailed Explanation
Co²⁺ has a 3d⁷ configuration, resulting in 3 unpaired electrons. The spin-only magnetic moment is calculated using the formula μ = √(n(n+2)), where n is the number of unpaired electrons. For Co²⁺, μ = √(3(3+2)) = 3.87 BM.
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