Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-diagram based-Medium-Class 12
Consider a galvanic cell diagram where a standard hydrogen electrode is connected as the anode and a copper half-cell as the cathode. Which equation correctly represents the measured emf of this cell at 298 K?
A
Eo = Eo(Cu2+/Cu) - Eo(H+/H2)
B
Eo = Eo(H+/H2) - Eo(Cu2+/Cu)
C
Eo = Eo(Cu2+/Cu) + Eo(H+/H2)
D
Eo = Eo(Cu2+/Cu) * Eo(H+/H2)
Correct Answer
Option A
Detailed Explanation
The emf of the cell is calculated as the difference between the standard electrode potentials of the cathode and anode. Since Eo(H+/H2) is zero, Eo = Eo(Cu2+/Cu) - 0.
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