Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Hard-Class 12
Given the cell potential equation for a Daniell cell: E(cell) = E°(cell) - (RT/2F) ln([Zn2+]/[Cu2+]), calculate the cell potential at 298 K if E°(cell) is 1.10 V, [Zn2+] is 0.01 M and [Cu2+] is 1 M.
A
1.16 V
B
1.04 V
C
0.98 V
D
1.22 V
Correct Answer
Option A
Detailed Explanation
Using the Nernst equation for the Daniell cell: E(cell) = 1.10 V - (0.059/2) log(0.01/1) = 1.10 V + 0.059 V = 1.16 V.
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