NEET2022Chemistry-Electrochemistry
NEET 2022 Chemistry Electrode Potential MCQ Question
Type: MCQ-conceptual-Medium-Class 12
Given below are half cell reactions:
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O, E° = +1.51 V
1/2 Ω₂ + 2H⁺ + 2e⁻ → H₂O, E° = +1.23 V
Will the permanganate ion, MnO₄⁻ liberate O₂ from water in the presence of an acid?
A
Yes, because E°cell = +2.733 V
B
No, because E°cell = -2.733 V
C
Yes, because E°cell = +0.287 V
D
No, because E°cell = -0.287 V
Correct Answer
Option D
Detailed Explanation
The permanganate ion will not liberate O₂ from water because the overall cell potential is negative, indicating a non-spontaneous reaction.
Found an issue with this question?