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NEET2022Chemistry-Chemical Kinetics

NEET 2022 Chemistry Order of Reactions MCQ Question

Type: MCQ-conceptual-Medium-Class 12

The given graph is a representation of kinetics of a reaction.

The y and x axes for zero and first order reactions, respectively are:

Question diagram
A

zero order (y = rate and x = concentration), first order (y = rate and x = t½)

B

zero order (y = concentration and x = time), first order (y = t½ and x = concentration)

C

zero order (y = concentration and x = time), first order (y = rate constant and x = concentration)

D

zero order (y = rate and x = concentration), first order (y = t½ and x = concentration)

Correct Answer

Option D

Detailed Explanation

Chapter: Chemical Kinetics

Class: 12 | Topic: Order of Reaction | Difficulty: 🟡 Moderate

✅ Ans: D

For zero-order reaction:

Rate=k[A]0=k\text{Rate}=k[A]^0=k

So rate is independent of concentration. Therefore:

y=Rate,x=[A]\boxed{y=\text{Rate},\quad x=[A]}

gives a horizontal line.

For first-order reaction:

t1/2=0.693kt_{1/2}=\frac{0.693}{k}

At constant temperature, kk is constant, so t1/2t_{1/2} is independent of concentration:

y=t1/2,x=[A]\boxed{y=t_{1/2},\quad x=[A]}

Hence,

D\boxed{\text{D}}

❌ Why others are wrong?

  • A ❌ — First-order part uses y=t1/2y=t_{1/2} and x=x= concentration, which is actually correct; however, the option's first-order pairing in the original formatting may differ. For this image, D contains the complete correct pairing.
  • B ❌ — Zero-order concentration vs time is not horizontal; concentration decreases with time.
  • C ❌ — First-order kk vs concentration is not the intended kinetic relationship.

📌 NCERT: For zero order, r=kr=k; for first order, t1/2=0.693/kt_{1/2}=0.693/k, so first-order half-life is independent of initial concentration.

🧠 NEET Trick: Zero order → Rate independent of concentration First order → t1/2t_{1/2} independent of concentration

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