NEET2026Chemistry-Chemical Kinetics

NEET 2026 Chemistry Arrhenius Equation MCQ Question

Type: MCQ-numerical-Medium-Class 12

Given below is an expression for the rate constant of a first-order reaction occurring at a certain temperature, T (K). ln k = 14.³⁴⁻ 1.25×104T\frac{1.25 \times 10^4}{T} The energy of activation in kcal mol⁻¹ for the reaction is : (Given: k in s⁻¹, R = 1.987 cal mol⁻¹ K⁻¹)

A

24.84

B

14.34

C

18.63

D

12.42

Correct Answer

Option A

Detailed Explanation

The expression ln k = A - EaRT\frac{E_a}{RT} is used to find the activation energy. Comparing with the given equation, Ea=1.25×104×RE_a = 1.25 \times 10^4 \times R. Substituting R = 1.987 cal mol⁻¹ K⁻¹, we get Ea=24.84E_a = 24.84 kcal mol⁻¹.

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