Chemistry-(general)

NEET Chemistry (general) MCQ Question

Type: MCQ-numerical-Medium-Class 11

Calculate the Gibbs free energy change (∆G ) for a reaction with an equilibrium constant (K) of 10 at 300 K. Use R = 8.314 J K⁻¹ mol⁻¹.

A

-5.71 kJ/mol

B

-7.61 kJ/mol

C

5.71 kJ/mol

D

7.61 kJ/mol

Correct Answer

Option A

Detailed Explanation

The Gibbs free energy change ∆G  is related to the equilibrium constant by the equation ∆G  = -RT ln K. Substituting the given values, ∆G  = -8.314 * 300 * ln(10) = -5.71 kJ/mol.

Found an issue with this question?