Chemistry-First Law
NEET Chemistry First Law MCQ Question
Type: MCQ-diagram based-Hard-Class 11
Consider a diagram representing an isolated system in which no heat or work is exchanged with the surroundings. Which statement correctly describes the change in internal energy (∆U) for this system?
A
∆U remains constant because q = 0 and w = 0.
B
∆U increases because the system is isolated.
C
∆U decreases due to spontaneous reactions within the system.
D
∆U changes depending on the initial and final states.
Correct Answer
Option A
Detailed Explanation
In an isolated system, no heat (q) or work (w) is transferred, so ∆U = q + w = 0. Therefore, the internal energy remains constant.
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