Chemistry-(general)
NEET Chemistry (general) MCQ Question
Type: MCQ-numerical-Hard-Class 11
Calculate the de Broglie wavelength of an electron moving with a velocity of 2.19 × 10^6 ms–1 in Bohr’s first orbit.
A
32 × 10^-10 m
B
67 × 10^-9 m
C
5.56 × 10^-11 m
D
42 × 10^-10 m
Correct Answer
Option A
Detailed Explanation
Using the de Broglie wavelength formula, λ = h/mv, where h is Planck’s constant (6.626 × 10^-34 Js), m is the mass of an electron (9.109 × 10^-31 kg), and v is the velocity (2.19 × 10^6 ms–1), we calculate λ to be approximately 3.32 × 10^-10 m.
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