NEET 2024 Chemistry Limiting Reactant Calculation MCQ Question
1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to
Zero mg
200 mg
750 mg
250 mg
Correct Answer
Detailed Explanation
The moles of HCl = 0.025 L × 0.75 mol/L = 0.01875 mol. The moles of NaOH = 1 g / 40 g/mol = 0.025 mol. After reaction, 0.025 - 0.01875 = 0.00625 mol NaOH remains, which is 0.00625 mol × 40 g/mol = 250 mg.
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