NEET2023Chemistry-Stoichiometry
NEET 2023 Chemistry Chemical Reactions and Calculations Numerical Question
Type: Numerical-numerical-Medium-Class 11
The right option for the mass of CO₂ produced by heating 20 g of 20% pure limestone is (Atomic mass of Ca = 40)
CaCO₃ ―――→1200 K CaO + CO₂
A
1.76 g
B
2.64 g
C
1.32 g
D
1.12 g
Correct Answer
Option A
Detailed Explanation
20 g of limestone contains 4 g of CaCO3 (20% purity). The molar mass of CaCO3 is 100 g/mol. Thus, 4 g corresponds to 0.04 mol. Heating CaCO3 produces CO2, and 0.04 mol of CaCO3 produces 0.04 mol of CO2, which is 1.12 g.
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