NEET Chemistry Henry's Law MCQ Question
The Henry's law constant for O₂ dissolved in water is 4.34 × 10⁴ atm at certain temperature. If the partial pressure of O₂ in a gas mixture that is in equilibrium with water is 0.434 atm, what is the mole fraction of O₂ in the solution?
1 × 10⁻⁵
1 × 10⁻⁴
2 × 10⁻⁵
1 × 10⁻⁶
Correct Answer
Detailed Explanation
Using Henry's law: mole fraction = partial pressure / Henry's constant = 0.434 / 4.34 × 10⁴.
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