Chemistry-Oxidation Number

NEET Chemistry Oxidation Number MCQ Question

Type: MCQ-diagram based-Medium-Class 11

A diagram illustrates the reaction between MnO₄⁻ (aq) and I⁻ (aq) in basic medium, forming MnO₂ (s) and I₂ (s). Which element undergoes a change in oxidation number, and what is the change?

Question diagram
A

Manganese; it decreases from +7 to +4.

B

Iodine; it increases from -1 to 0.

C

Manganese; it increases from +4 to +7.

D

Iodine; it decreases from 0 to -1.

Correct Answer

Option A

Detailed Explanation

In the reaction given, MnO₄⁻ is reduced to MnO₂, indicating manganese's oxidation number decreases from +7 to +4. This is a redox change where manganese is reduced.

Found an issue with this question?