Chemistry-Oxidation Number
NEET Chemistry Oxidation Number Match the Following Question
Type: Match the Following-match the column-Medium-Class 11
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Oxidation number of carbon in C3O2 | (i) 2.5 |
| (b) Oxidation number of sulphur in Na2S4O6 | (ii) 4/3 |
| (c) Oxidation number of bromine in Br3O8 | (iii) 16/3 |
| (d) Oxidation number of oxygen in CO32– | (iv) -2 |
A
a-ii, b-i, c-iii, d-iv
B
a-iii, b-iv, c-i, d-ii
C
a-i, b-ii, c-iv, d-iii
D
a-iv, b-iii, c-ii, d-i
Correct Answer
Option A
Detailed Explanation
The oxidation number of carbon in C3O2 is 4/3, sulphur in Na2S4O6 is 2.5, bromine in Br3O8 is 16/3, and in CO32–, oxygen has an oxidation number of -2. All pairs in option A are correct as per the provided NCERT context.
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