Chemistry-Oxidation Number
NEET Chemistry Oxidation Number Match the Following Question
Type: Match the Following-match the column-Easy-Class 11
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Cr in Cr2O7^2– | (i) +4 |
| (b) S in SO3^2– | (ii) +6 |
| (c) Cr in Cr3+ | (iii) +3 |
| (d) S in SO4^2– | (iv) +2 |
A
a-ii, b-i, c-iii, d-iv
B
a-i, b-ii, c-iii, d-iv
C
a-ii, b-iii, c-iv, d-i
D
a-iv, b-ii, c-iii, d-i
Correct Answer
Option A
Detailed Explanation
In the dichromate ion (Cr2O7^2–), chromium has an oxidation number of +6, and in Cr3+, it is +3. Sulphur in the sulphite ion (SO3^2–) is +4, and in the sulphate ion (SO4^2–), it is +6. Thus, the correct matching is a-ii, b-i, c-iii, d-iv.
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