Chemistry-Oxidation Number
NEET Chemistry Oxidation Number Match the Following Question
Type: Match the Following-match the column-Hard-Class 11
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Oxidation state of chromium in Cr2O7^2– | (i) +6 |
| (b) Oxidation state of sulphur in SO3^2– | (ii) +4 |
| (c) Oxidation state of carbon in C3O2 | (iii) (4/3) |
| (d) Oxidation state of bromine in Br3O8 | (iv) (16/3) |
A
a-i, b-ii, c-iii, d-iv
B
a-ii, b-i, c-iv, d-iii
C
a-iv, b-iii, c-i, d-ii
D
a-iii, b-iv, c-ii, d-i
Correct Answer
Option A
Detailed Explanation
The oxidation state of chromium in Cr2O7^2– is +6, sulphur in SO3^2– is +4, carbon in C3O2 has an oxidation number of (4/3), and bromine in Br3O8 has an oxidation number of (16/3) as per the examples given in the NCERT context.
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