NEET Chemistry Balancing Redox Reactions Match the Following Question
Match Column-I with Column-II.
| Column-I | Column-II |
|---|---|
| (a) Oxidation half-reaction | (i) 2MnO 4 – (aq) + 4H 2 O(l) + 6e – → 2MnO 2 (s) + 8OH – (aq) |
| (b) Reduction half-reaction | (ii) 6I – (aq) → 3I 2 (s) + 6e – |
| (c) Net reaction | (iii) 6I – (aq) + 2MnO 4 – (aq) + 4H 2 O(l) → 3I 2 (s) + 2MnO 2 (s) + 8OH – (aq) |
| (d) Number of electrons balanced | (iv) 6e – |
a-i, b-ii, c-iii, d-iv
a-ii, b-i, c-iv, d-iii
a-iii, b-iv, c-i, d-ii
a-iv, b-iii, c-ii, d-i
Correct Answer
Detailed Explanation
The oxidation half-reaction involves the loss of electrons, while the reduction half-reaction involves the gain of electrons, leading to the net reaction of both processes. The matching in option A correctly reflects the relationships among these components in the balancing of redox reactions.
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