NEET 2026 Chemistry Solubility Product MCQ Question
In a qualitative analysis, Bi³⁺ is detected by appearance of precipitate of BiO(OH)(s). Calculate pH when the following equilibrium exists at 298 K. BiO(OH)(s) ⇌ BiO⁺(aq) + OH⁻(aq), K = 4 × 10⁻¹⁰ (Given : log2 = 0.3010)
8.714
4.699
5.286
9.301
Correct Answer
Detailed Explanation
The equilibrium constant K is given by K = [BiO⁺][OH⁻]. Solving for [OH⁻], we find s = √K = √(4 × 10⁻¹⁰) = 2 × 10⁻⁵ M. The pH is calculated using the relation [H⁺] = Kᵥ/[OH⁻] = 1 × 10⁻⁹, giving pH = -log[H⁺] =⁹⁺ log2 = 9.301.
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