NEET2019Chemistry-Equilibrium
NEET 2019 Chemistry Solubility Product MCQ Question
Type: MCQ-numerical-Hard-Class 11
pH of a saturated solution of Ca(OH)₂ is 9. The solubility product (Kₛₚ) of Ca(OH)₂ is
A
0.25 × 10⁻¹⁰
B
0.125 × 10⁻¹⁵
C
0.5 × 10⁻¹⁰
D
0.5 × 10⁻¹⁵
Correct Answer
Option D
Detailed Explanation
The pH of 9 indicates a hydroxide ion concentration of 10⁻⁵ M. Using the solubility product expression for Ca(OH)₂, Kₛₚ = [Ca²⁺][OH⁻]², we find Kₛₚ = 0.125 × 10⁻¹⁵.
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