NEET Chemistry Chemical Equilibrium MCQ Question
Consider a diagram representing the equilibrium system of H2O (g) + CO (g) ⇌ H2 (g) + CO2 (g). If 1 mole each of H2O and CO are placed in a 10 L vessel at 725 K, and 40% of water reacts at equilibrium, what is the equilibrium constant for this reaction?
Kc = 0.16
Kc = 0.24
Kc = 0.40
Kc = 0.64
Correct Answer
Detailed Explanation
At equilibrium, 0.4 moles of H2O have reacted, forming 0.4 moles each of H2 and CO2. Kc is calculated using equilibrium concentrations: Kc = ([H2][CO2])/([H2O][CO]) = (0.040.04)/(0.060.06) = 0.64.
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