NEET2022Chemistry-Electrochemistry
NEET 2022 Chemistry Nernst Equation MCQ Question
Type: MCQ-numerical-Medium-Class 12
Find the emf of the cell in which the following reaction takes place at 298 K. Ni(s) + 2Ag⁺(0.001 M) → Ni²⁺(0.001 M) + 2Ag(s) (Given that E°cell = 1.05 V, 2.303RT/F = 0.059 at 298 K)
A
10.4115 V
B
1.05 V
C
1.0385 V
D
1.385 V
Correct Answer
Option C
Detailed Explanation
Using the Nernst equation, E = E° - (0.059/n) log(Q), where Q = [Ni²⁺]/[Ag⁺]² = 0.001/0.001² = 1000. Substituting values gives E = 1.0385 V.
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