AIPMT PRELIMS2005Physics-Nuclear Physics
AIPMT PRELIMS 2005 Physics Nuclear Reactions MCQ Question
Type: MCQ-numerical-Hard-Class 12
In the reaction ²¹H + ³¹H → ⁴₂He + ¹₀n, if the binding energies of ²¹H, ³¹H and ⁴₂He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is:
A
c + a - b
B
c - a - b
C
a + b + c
D
b-c-a
Correct Answer
Option B
Detailed Explanation
The energy released in a nuclear reaction is the difference in the total binding energies of the products and reactants. Here, it is (c + a) - b.
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