A charge having q/m equal to 10⁸ c/kg and with velocity 3 × 10⁶ m/s enters into a uniform magnetic field B = 0.3 tesla at an angle 30° with direction of field. Then radius of curvature will be :
A
0.01 cm
B
0.5 cm
C
1 cm
D
2 cm

Question

A charge having q/m equal to 10⁸ c/kg and with velocity 3 × 10⁶ m/s enters into a uniform magnetic field B = 0.3 tesla at an angle 30° with direction of field. Then radius of curvature will be :

Accepted Answer

0.5 cm

Answer

0.01 cm

Answer

1 cm

Answer

2 cm

AIPMT PRELIMS 2000 Physics Motion in Magnetic Field MCQ Question

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