AIPMT PRELIMS2003Physics-Electrostatics

AIPMT PRELIMS 2003 Physics Coulomb's Law MCQ Question

Type: MCQ-conceptual-Medium-Class 12

An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius r. The coulomb force F\vec{F} between the two is -(where K=14πε0\text{K} = \frac{1}{4\pi\varepsilon_0})

A

Ke2r2r^K \frac{e^2}{r^2} \hat{r}

B

Ke2r3r^-K \frac{e^2}{r^3} \hat{r}

C

Ke2r3rK \frac{e^2}{r^3} \vec{r}

D

Ke2r3r-K \frac{e^2}{r^3} \vec{r}

Correct Answer

Option D

Detailed Explanation

The force between the electron and the nucleus is attractive, hence the negative sign. The formula for the Coulomb force is given by F = -K rac{e^2}{r^2} \hat{r}.

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