AIPMT PRELIMS2011Physics-Modern Physics
AIPMT PRELIMS 2011 Physics Photoelectric Effect MCQ Question
Type: MCQ-numerical-Medium-Class 12
Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum speeds of emitted electrons will be
A
1 : 5
B
1 : 4
C
1 : 2
D
1 : 1
Correct Answer
Option C
Detailed Explanation
Using the photoelectric equation, KE_max = hf - φ, where φ is the work function. For 1 eV, KE_max = 1 - 0.5 = 0.5 eV. For 2.5 eV, KE_max = 2.5 - 0.5 = 2 eV. The ratio of speeds is √(0.5/2) = 1:2.
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