AIPMT PRELIMS 2006 Physics Photoelectric Effect MCQ Question
When photons of energy hν fall on an aluminium plate (of work function E₀), photoelectrons of maximum kinetic energy K are ejected. If the frequency of the radiation is doubled, the maximum kinetic energy of the ejected photoelectrons will be :
K + E₀
2K
K
K + hν
Correct Answer
Detailed Explanation
Doubling the frequency doubles the photon energy to 2hν. The kinetic energy of the photoelectrons is given by K = hν - E₀, so doubling the frequency gives K = 2hν - E₀.
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