Back to Practice
AIPMT PRELIMS2009Physics-Current Electricity

AIPMT PRELIMS 2009 Physics Galvanometer to Ammeter Conversion MCQ Question

Type: MCQ-numerical-Medium-Class 12

A galvanometer having a coil resistance of 60 Ω shows full scale deflection when a current of 1.0 amp passes through it. It can be converted into an ammeter to read currents up to 5.0 amp by:

A

putting in series a resistance of 15 Ω

B

putting in series a resistance of 240 Ω

C

putting in parallel a resistance of 15 Ω

D

putting in parallel a resistance of 240 Ω

Correct Answer

Option C

Detailed Explanation

To convert the galvanometer to an ammeter, a shunt resistance is used. The shunt resistance is calculated using the formula S=IgI−Ig×GS = \frac{I_g}{I - I_g} \times G. For the given values, S=15ΩS = 15 \Omega, so a 15 Ω resistor is put in parallel.

Found an issue with this question?

Related Questions

Explore More Questions

All Physics QuestionsCurrent Electricity QuestionsAIPMT PRELIMS 2009 PYQ