AIPMT PRELIMS 2009 Physics Electric Field MCQ Question
The mean free path of electrons in a metal is 4 × 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m:
5 × 10⁻¹¹
8 × 10⁻¹¹
5 × 10⁷
8 × 10⁷
Correct Answer
Detailed Explanation
The electric field E is given by E = V/d. Here, V = 2 eV and d = 4 × 10⁻⁸ m. Converting eV to joules, we get E = (2 × 1.6 × 10⁻¹⁹)/(4 × 10⁻⁸) = 5 × 10⁷ V/m.
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