AIPMT PRELIMS2004Physics-Atomic Physics
AIPMT PRELIMS 2004 Physics Hydrogen Atom MCQ Question
Type: MCQ-numerical-Medium-Class 12
Energy E of a hydrogen atom with principal quantum number n is given by E = -13.6/n² eV. The energy of a photon ejected when the electron jumps from n = 3 state to n = 2 state of hydrogen is approximately :-
A
0.85 eV
B
3.4 eV
C
1.9 eV
D
1.5 eV
Correct Answer
Option C
Detailed Explanation
The energy difference between the two states is calculated using the formula for energy levels, resulting in 3.4 eV.
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