AIPMT PRELIMS 2012 Physics Beat Frequency MCQ Question
Two sources of sound placed close to each other, are emitting progressive waves given by y₁ = 4 sin 600 πt and y₂ = 5 sin 608 πt. An observer located near these two sources of sound will hear:
4 beats per second with intensity ratio 81 : 1 between waxing and waning
4 beats per second with intensity ratio 25 : 16 between waxing and waning
8 beats per second with intensity ratio 25 : 16 between waxing and waning
8 beats per second with intensity ratio 81 : 1 between waxing and waning
Correct Answer
Detailed Explanation
The beat frequency is calculated as the difference in frequencies of the two waves, which is 608 - 600 = 8 Hz. However, the intensity ratio determines the perceived beats, leading to 4 beats per second with an intensity ratio of 81:1.
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