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AIPMT PRELIMS2009Physics-Thermodynamics

AIPMT PRELIMS 2009 Physics Heat Transfer MCQ Question

Type: MCQ-conceptual-Medium-Class 11

The two ends of a rod of length L and a uniform cross-sectional area A are kept at two temperatures T1T_1 and T2T_2 (T1>T2T_1 > T_2). The rate of heat transfer, dQdt\frac{dQ}{dt}, through the rod in a steady state is given by:

A

k(T1−T2)LA\frac{k(T_1 - T_2)}{LA}

B

kLΔ(T1−T2)kL \Delta (T_1 - T_2)

C

kA(T1−T2)L\frac{kA(T_1 - T_2)}{L}

D

kL(T1−T2)A\frac{kL(T_1 - T_2)}{A}

Correct Answer

Option C

Detailed Explanation

The rate of heat transfer through a rod in a steady state is given by Fourier's law of heat conduction: dQdt=kA(T1−T2)L\frac{dQ}{dt} = \frac{kA(T_1 - T_2)}{L}, where k is the thermal conductivity.

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