AIPMT PRELIMS2009Physics-Thermodynamics
AIPMT PRELIMS 2009 Physics First Law of Thermodynamics MCQ Question
Type: MCQ-conceptual-Medium-Class 11
The internal energy change in a system that has absorbed 2 Kcals of heat and done 500 J of work is:
A
6400 J
B
5400 J
C
7900 J
D
8900 J
Correct Answer
Option C
Detailed Explanation
The change in internal energy (ΔU) is given by ΔU = Q - W, where Q is the heat absorbed and W is the work done. Converting 2 Kcals to Joules (2 × 4.2 × 1000 J) and subtracting the work done (500 J), we get ΔU = 7900 J.
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