AIPMT PRELIMS2001Physics-Wien's Displacement Law

AIPMT PRELIMS 2001 Physics Black Body Radiation MCQ Question

Type: MCQ-conceptual-Medium-Class 11

A black body has wavelength λₘ corresponding to maximum energy at 2000 K. Its wavelength corresponding to maximum energy at 3000 K will be:

A

3/2 λₘ

B

2/3 λₘ

C

16/81 λₘ

D

81/16 λₘ

Correct Answer

Option B

Detailed Explanation

According to Wien's Displacement Law, the wavelength corresponding to maximum energy (λmax\lambda_{max}) of a black body is inversely proportional to its temperature (TT). This is mathematically expressed as: λmaxT=b\lambda_{max} T = b where bb is Wien's displacement constant. For the first case at 2000 K, we have: λm2000=b\lambda_{m} \cdot 2000 = b. For the second case at 3000 K, we can express it as: λmax3000=b\lambda_{max}' \cdot 3000 = b. By equating the two expressions for bb, we get: λm2000=λmax3000\lambda_{m} \cdot 2000 = \lambda_{max}' \cdot 3000. Rearranging gives us: λmax=20003000λm=23λm\lambda_{max}' = \frac{2000}{3000} \lambda_{m} = \frac{2}{3} \lambda_{m}. Therefore, the correct answer is B.

The other options are incorrect because they do not satisfy the relationship established by Wien's Displacement Law. For example, option A (32λm\frac{3}{2} \lambda_{m}) suggests an increase in wavelength with temperature, which contradicts the law. Similarly, options C and D do not align with the inverse relationship between wavelength and temperature.

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