AIPMT PRELIMS2007Physics-Rotational Motion
AIPMT PRELIMS 2007 Physics Torque and Angular Acceleration MCQ Question
Type: MCQ-conceptual-Medium-Class 11
Weight of the rod will produce torque, τ = mg × ℓ/2. Also, τ = Iα. Where, I is the moment of inertia = mℓ²/3 and α is the angular acceleration. Therefore, mℓ²/3 α = mg × ℓ/2 ⇒ α = 3g/2ℓ.
Correct Answer
Option C
Detailed Explanation
The torque produced by the weight of the rod is balanced by the angular acceleration. Using the formula τ = Iα and substituting the values, we find that α = 3g/2ℓ.
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