AIPMT PRELIMS2009Physics-Simple Harmonic Motion
AIPMT PRELIMS 2009 Physics Pendulum Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
A
πa/T
B
3π²a/T
C
πa√3/T
D
πa√3/2T
Correct Answer
Option C
Detailed Explanation
The speed of the pendulum at x = a/2 can be calculated using the formula v = ω√(a² - x²). Substituting x = a/2 gives v = πa√3/T.
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