AIPMT PRELIMS2005Physics-Oscillations
AIPMT PRELIMS 2005 Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is:
A
2 Hz
B
1.5 Hz
C
0.5 Hz
D
1 Hz
Correct Answer
Option D
Detailed Explanation
The maximum speed in simple harmonic motion is given by v_max = ωA, where ω is the angular frequency and A is the amplitude. Given v_max = 31.4 cm/s and A = 5 cm, ω = v_max/A = 31.4/5 = 6.28 rad/s. The frequency f is ω/2π = 6.28/2π = 1 Hz.
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