AIPMT PRELIMS2000Physics-Oscillations
AIPMT PRELIMS 2000 Physics Simple Harmonic Motion MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two spherical bob of masses Mₐ and Mᵦ are hung vertically from two strings of length ℓₐ and ℓᵦ respectively. They are executing SHM with frequency relation fₐ = 2fᵦ. Then :
A
ℓₐ = ℓᵦ / 4
B
ℓₐ = 4ℓᵦ
C
ℓₐ = 2ℓᵦ & Mₐ = 2Mᵦ
D
ℓₐ = ℓᵦ / 2 & Mₐ = Mᵦ / 2
Correct Answer
Option A
Detailed Explanation
The frequency of a pendulum is inversely proportional to the square root of its length. Given fₐ = 2fᵦ, ℓₐ must be 4 times ℓᵦ.
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