AIPMT PRELIMS 2009 Physics Equations of Motion MCQ Question
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is S₁ and that covered in the first 20 seconds is S₂, then:
S₂ = 3S₁
S₂ = 4S₁
S₂ = S₁
S₂ = 2S₁
Correct Answer
Detailed Explanation
The distance covered by an object under constant acceleration is proportional to the square of the time. Therefore, S₂/S₁ = (t₂/t₁)² = (20/10)² = 4. Hence, S₂ = 4S₁.
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