AIPMT PRELIMS2005Physics-Kinematics
AIPMT PRELIMS 2005 Physics Relative Motion MCQ Question
Type: MCQ-conceptual-Medium-Class 11
Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is :
A
a/(√(v²⁺ v21))
B
a/(a/√(v²⁻ v21))
C
a/(v - v1)
D
a/(v + v1)
Correct Answer
Option B
Detailed Explanation
The relative velocity of the boy at A with respect to the boy at B is v + v1. Therefore, the time taken to catch up is the distance divided by the relative velocity.
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