AIPMT PRELIMS2008Physics-Laws of Motion
AIPMT PRELIMS 2008 Physics Conservation of Momentum MCQ Question
Type: MCQ-conceptual-Medium-Class 11
A particle of mass m is projected with velocity v making an angle of 45° with the horizontal from level ground. When the particle lands on the level ground the magnitude of the change in its momentum will be -
A
mv√2
B
zero
C
2 mv
D
mv/√2
Correct Answer
Option A
Detailed Explanation
The change in momentum is calculated using the formula Δp = 2mv cos(θ). For θ = 45°, Δp = 2mv cos(45°) = mv√2.
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