AIPMT PRELIMS 2009 Physics Kepler's Laws MCQ Question
The Figure shows elliptical orbit of a planet m about the sum S. The shaded area SCD is twice the shaded area SAB. If t₁ is the time for the planet of move from C to D and t₂ is the time to move from A to B then:
t₁ = 4t₂
t₁ = 2t₂
t₁ = t₂
t₁ > t₂
Correct Answer
Detailed Explanation
According to Kepler's second law, the areal velocity is constant. Since the area SCD is twice the area SAB, the time t₁ must be twice t₂ to maintain the constant areal velocity.
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