AIPMT PRELIMS2003Chemistry-Thermodynamics
AIPMT PRELIMS 2003 Chemistry Gibbs Free Energy MCQ Question
Type: MCQ-numerical-Hard-Class 11
The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm⁻³, respectively. If the standard free energy difference (ΔG°) is equal to 1895 J mol⁻¹, the pressure at which graphite will be transformed into diamond at 298 K is -
A
9.92 × 10⁸ Pa
B
9.92 × 10⁷ Pa
C
9.92 × 10⁶ Pa
D
9.92 × 10⁵ Pa
Correct Answer
Option A
Detailed Explanation
The pressure can be calculated using the formula ΔG = VΔP, where V is the volume change. Given the densities, the volume change can be calculated, and substituting the values gives the pressure as 9.92 × 10⁸ Pa.
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