AIPMT PRELIMS2001Chemistry-Molecular Weight
AIPMT PRELIMS 2001 Chemistry Calculations MCQ Question
Type: MCQ-numerical-Hard-Class 11
Sp. vol. of cylinderical virus particle is 6.02 × 10⁻² cc/gm. Whose radius and length are 7 Å & 10Å respectively. If Nₐ = 6.02 × 10²³. Find mol. wt. of virus : -
A
54 kg/mol.
B
54 × 10³ kg/mol.
C
08 × 10⁴ kg/mol.
D
08 × 10³ kg/mol.
Correct Answer
Option A
Detailed Explanation
Using the specific volume and Avogadro's number, calculate the molar mass: Molar mass = specific volume × Nₐ = 6.02 × 10⁻² × 6.02 × 10²³ = 3.08 × 10⁴ kg/mol.
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