AIPMT PRELIMS2012Chemistry-Equilibrium
AIPMT PRELIMS 2012 Chemistry Solubility Product MCQ Question
Type: MCQ-numerical-Hard-Class 11
pH of a saturated solution of Ba(OH)₂ is 12. The value of solubility product (Kₛₚ) of Ba(OH)₂ is
A
5.0 × 10⁻⁶
B
3.3 × 10⁻⁷
C
5.0 × 10⁻⁷
D
4.0 × 10⁻⁶
Correct Answer
Option C
Detailed Explanation
Given pH = 12, pOH = 2, [OH⁻] = 10⁻². Ba(OH)₂ dissociates to give 2OH⁻, so solubility x = 5 × 10⁻³. Kₛₚ = (2x)²x = 5 × 10⁻⁷.
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